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[Ideas For Design]
Resistive Dummy Load Draws Constant Current From 1.2 To 50 V

John Guy  |   ED Online ID #4056  |   April 16, 2001


This dummy-load circuit has been in use at Maxim for more than 10 years (see the figure). It's useful for testing power supplies and power amplifiers as well as drivers for LEDs, relays, and solenoids. Plus, it overcomes the limitations of power rheostats, which are bulky and have coarse setting accuracy. The device also has an advantage over large, expensive power decade boxes, which provide limited resolution.

Unlike conventional resistive loads, the "dummy load" maintains a constant but adjustable load current for voltages in the range of 1.2 to 50 V. Both the power MOSFET and the sense resistor are used to dissipate the load power. Battery operation provides isolation while eliminating grounding problems.

The 10-turn potentiometer R6 affects accuracy and resolution. Consequently, it should be rated for at least 3% absolute accuracy and 0.2% or better linearity. (If desired, R6 can be replaced with a three-digit pushbutton potentiometer such as Bourns model 3680.) R6's wiper provides a reference to the op amp, whose input common-mode range includes ground. Feedback ensures that the wiper voltage appears across the sense resistor (R9), thereby forcing a desired load current through the MOSFET.

Bias current for the op amp (3 nA maximum) flows through the series combination of RA, RB, RC, and R10. Multiplying this current by the sum of the four series resistors (100 Ω) yields a 300-nV error. This error voltage is small compared to the voltage presented by R6 at the op amp's noninverting terminal. Therefore, the resulting output-current error is insignificant. Capacitor C1 enhances stability by reducing bandwidth (already low by this point).

The series-connected, decade-weighted load resistors RA, RB, and RC yield four ranges of output-current capability. To set the range for a power-supply load, connect the positive lead of the supply to the "+" input of the load circuit and the negative load to one of the four return terminals.

For calibration, insert a battery and turn on the circuit. Then, connect the positive terminal of a 5-V/10-A power supply (in series with an ammeter that has a 4.5-digit display or better) to the "+" input of the dummy load. Next, connect the ground terminal of the power supply to the 10-A return of the load box. With R6 at full scale, adjust R3 so the ammeter reads precisely 10.00 A. To check the circuit's linearity, set R6 to exactly five turns and verify that the ammeter reads 5.00 A.

Calibrate the remaining ranges by regulating the values of RA, RB, and RC. Since each of these consists of three resistors in parallel, the value is best adjusted by changing the largest of the three parallel-connected resistors. For example, to regulate RA, set R6 at full scale and adjust the largest of the three resistors in R6 (100 Ω) until the ammeter reads 1.00 A. Then adjust the largest of the RB resistors for a 100-mA reading, and the largest of the RC resistors for a 10-mA reading.

The minimum operating current for the MAX6006 reference is 1 µA, yielding an overall supply current of only 18 µA. Given the 580-mA-hr rating of a 9-V battery, this circuit can operate continuously for several years. With its 15-µA maximum supply current and 25-µV typical offset voltage, the MAX480 is an excellent choice for this application.


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    Reader Comments

    Dear Sir Please tell me how to calculate load current,MCB,MCCB,ELCB ratings...........please give me the formulas.

    Anonymous -July 03, 2007

    1 - yes, the operating voltage can be reduced. Simply bias the reference voltage down to 0.5V by increasing R2 about 2x, can decreasing R10, RA, RB and RC by 1/2.

    2 - Good point. I always verify the stability, but so far have not seen instability. The op amp is sooo slow, the FET works on its own as a current source as it is biased in saturation.

    3 - Simply use a higher voltage FET, and use multiple FETs. Each additional FET needs its own R8, but each FET source is connected to all other sources, each drain is connected to all other drains. I would suggest an active cooling system.

    4 - AC is out of the question for this. This was designed to have almost no AC response to ensure stability (see # 2 above)Also, the body diode of the FET will turn on if the polarity is reversed on the output.

    JG

    John Guy -May 31, 2007   (Article Rating: )

    I am looking for , 1. AC 230 V 50 Hz dummy load up to 10 KVA 2. DC 12 - 70 V in put dummy load with currint up to 150 Amps (variable)

    Audry -February 10, 2006

    Sir,

    Great article. What changes to be made to upgrade this to 600W with adjustable load current for voltages in the range of 1.2 to 60 V.

    Sreenivas -October 17, 2005

    My question is the stability of this circuit. Imagine that you use this current source to verify a switcher design and that switcher-under-test is having a 10V output with a 1 (maybe even 2) volts of ripple voltage @ 500kHz.At this point I guess this schematic starts to oscillate? I do not mean to say that 2V of ripple (20%) is normal, but is there something to improve? Thanks in advance.

    Kalle Arulaane -August 09, 2005

    Is there a way to lower the operating voltage? I'm looking to build a constant current load that will operate with load voltages down to 0.5 V. Thanks. Great article.

    Terence O'Beirne -October 25, 2004

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